WebRewrite csc(θ) csc ( θ) in terms of sines and cosines. Multiply by the reciprocal of the fraction to divide by 1 cos(θ) 1 cos ( θ). Convert from cos(θ) sin(θ) cos ( θ) sin ( θ) to … WebJun 5, 2024 · Step 1: Use reciprocal identity csc x = 1 sin x Step 2: Square both sides csc 2 x = 1 sin 2 x Step 3: Apply Pythagorean identity csc 2 x = 1 1 − cos 2 Step 4: Obtain the square root of both sides csc x = ± 1 1 − cos 2 The correct answer is supposed to be: csc x = ± 1 − cos 2 x 1 − cos x 2 trigonometry Share Cite Follow edited Jun 5, 2024 at 10:47
Simplify (csc(theta))/(cot(theta)) Mathway
Webcsc theta = 3, cost theta less than 0 WebUse the given conditions to find the values of all six trigonometric functions. (If an answer is undefined, enter UNDEFINED.) sin (θ) = − 6 5 , cos (θ) > 0 sin (θ) = cos (θ) = tan (θ) = csc (θ) = sec (θ) = cot (θ) = lyric removal tool
Solve for ? cot(theta)=cos(theta)csc(theta) Mathway
WebNov 14, 2024 · Since x = cot(θ) then 1/x = tan(θ) so: θ = tan -1 (1/0.5099407098) = 1.099227812 radians but tan(θ) is positive in Q1 and Q3 the Q3 angle would be the Q1 angle plus π which would be 4.240820466 however when we try both of these in the original equation, only 1.099227812 works so the other is an extraneous solution. Web(10 pts) Find the exact values of the six trigonometric ratios of θ if sec θ = 5 7 , and csc θ < 0. sin θ = cos θ = tan θ = csc θ = sec θ = cot θ = WebFeb 25, 2024 · cotθ = −√15, secθ = − 4 √15 and cscθ = 4. Explanation: Let us consider the identity csc2θ = 1 +cot2θ as cscθ = 4, we have 16 = 1 +cot2θ and cot2θ = 15 and as cotθ < 0, cotθ = − √15 Therefore tanθ = − 1 √15 and sinθ = 1 4 As #tantheta=sintheta/costheta, this means cosθ = sinθ tanθ = 1 4 − 1 √15 = − √15 4 and secθ = − 4 √15 Answer link lyric remedy